Base | Representation |
---|---|
bin | 1100000111100000011111… |
… | …1101001001001100000011 |
3 | 1202011200022021120221010022 |
4 | 3001320013331021030003 |
5 | 3221241223214133443 |
6 | 44200320250524055 |
7 | 2543364245433245 |
oct | 301700775111403 |
9 | 52150267527108 |
10 | 13323122021123 |
11 | 4277339058762 |
12 | 15b213a73662b |
13 | 758498c2a015 |
14 | 340bb1d3a095 |
15 | 181871c09e68 |
hex | c1e07f49303 |
13323122021123 has 2 divisors, whose sum is σ = 13323122021124. Its totient is φ = 13323122021122.
The previous prime is 13323122021059. The next prime is 13323122021189. The reversal of 13323122021123 is 32112022132331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13323122021123 - 26 = 13323122021059 is a prime.
It is a super-2 number, since 2×133231220211232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13323122021092 and 13323122021101.
It is not a weakly prime, because it can be changed into another prime (13323122021023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661561010561 + 6661561010562.
It is an arithmetic number, because the mean of its divisors is an integer number (6661561010562).
Almost surely, 213323122021123 is an apocalyptic number.
13323122021123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13323122021123 is an equidigital number, since it uses as much as digits as its factorization.
13323122021123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 13323122021123 its reverse (32112022132331), we get a palindrome (45435144153454).
The spelling of 13323122021123 in words is "thirteen trillion, three hundred twenty-three billion, one hundred twenty-two million, twenty-one thousand, one hundred twenty-three".
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