Base | Representation |
---|---|
bin | 111110000010101010… |
… | …1000101110010101000 |
3 | 110201220021011000221102 |
4 | 1330011111011302220 |
5 | 4140330222313000 |
6 | 141112342100532 |
7 | 12424435136300 |
oct | 1740525056250 |
9 | 421807130842 |
10 | 133233401000 |
11 | 5155a866167 |
12 | 219a371a748 |
13 | c743a3936b |
14 | 663caaa600 |
15 | 36ebb5d3d5 |
hex | 1f05545ca8 |
133233401000 has 192 divisors, whose sum is σ = 363223083600. Its totient is φ = 45609984000.
The previous prime is 133233400969. The next prime is 133233401023. The reversal of 133233401000 is 104332331.
It can be written as a sum of positive squares in 8 ways, for example, as 33681792676 + 99551608324 = 183526^2 + 315518^2 .
It is a super-2 number, since 2×1332334010002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 39639320 + ... + 39642680.
Almost surely, 2133233401000 is an apocalyptic number.
133233401000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133233401000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (181611541800).
133233401000 is an abundant number, since it is smaller than the sum of its proper divisors (229989682600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133233401000 is a wasteful number, since it uses less digits than its factorization.
133233401000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4205 (or 4184 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 133233401000 its reverse (104332331), we get a palindrome (133337733331).
The spelling of 133233401000 in words is "one hundred thirty-three billion, two hundred thirty-three million, four hundred one thousand".
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