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133240012114503 = 3713194810282397
BaseRepresentation
bin11110010010111001011011…
…100101111000101001000111
3122110202121202112102021012010
4132102321123211320221013
5114431001021100131003
61151213341102025303
740031162465240610
oct3622713345705107
9573677675367163
10133240012114503
11394aa854307a28
1212b3a982578233
13594662cb38948
1424c8bcb1b8c07
151060d29d3d003
hex792e5b978a47

133240012114503 has 16 divisors (see below), whose sum is σ = 203186328491520. Its totient is φ = 76079426375136.

The previous prime is 133240012114493. The next prime is 133240012114523. The reversal of 133240012114503 is 305411210042331.

It is not a de Polignac number, because 133240012114503 - 28 = 133240012114247 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133240012114523) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2405113500 + ... + 2405168897.

It is an arithmetic number, because the mean of its divisors is an integer number (12699145530720).

Almost surely, 2133240012114503 is an apocalyptic number.

133240012114503 is a deficient number, since it is larger than the sum of its proper divisors (69946316377017).

133240012114503 is a wasteful number, since it uses less digits than its factorization.

133240012114503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4810283726.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 133240012114503 its reverse (305411210042331), we get a palindrome (438651222156834).

The spelling of 133240012114503 in words is "one hundred thirty-three trillion, two hundred forty billion, twelve million, one hundred fourteen thousand, five hundred three".

Divisors: 1 3 7 21 1319 3957 9233 27699 4810282397 14430847191 33671976779 101015930337 6344762481643 19034287444929 44413337371501 133240012114503