Base | Representation |
---|---|
bin | 111110000010111000… |
… | …0001110011111000001 |
3 | 110201220202112102211021 |
4 | 1330011300032133001 |
5 | 4140334032430442 |
6 | 141113154345441 |
7 | 12424552454326 |
oct | 1740560163701 |
9 | 421822472737 |
10 | 133240514497 |
11 | 51563884692 |
12 | 219a5b8b281 |
13 | c74535a12c |
14 | 663d9dcb4d |
15 | 36ec5b5e67 |
hex | 1f05c0e7c1 |
133240514497 has 2 divisors, whose sum is σ = 133240514498. Its totient is φ = 133240514496.
The previous prime is 133240514467. The next prime is 133240514501. The reversal of 133240514497 is 794415042331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102768971776 + 30471542721 = 320576^2 + 174561^2 .
It is a cyclic number.
It is not a de Polignac number, because 133240514497 - 227 = 133106296769 is a prime.
It is a super-3 number, since 3×1332405144973 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (133240514437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66620257248 + 66620257249.
It is an arithmetic number, because the mean of its divisors is an integer number (66620257249).
Almost surely, 2133240514497 is an apocalyptic number.
It is an amenable number.
133240514497 is a deficient number, since it is larger than the sum of its proper divisors (1).
133240514497 is an equidigital number, since it uses as much as digits as its factorization.
133240514497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 43.
The spelling of 133240514497 in words is "one hundred thirty-three billion, two hundred forty million, five hundred fourteen thousand, four hundred ninety-seven".
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