13324405133021 has 4 divisors (see below), whose sum is σ = 13406149949952. Its totient is φ = 13242660316092.

The previous prime is 13324405132999. The next prime is 13324405133183. The reversal of 13324405133021 is 12033150442331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13324405133021 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13324405133621) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40872408221 + ... + 40872408546.

It is an arithmetic number, because the mean of its divisors is an integer number (3351537487488).

Almost surely, 2^{13324405133021} is an apocalyptic number.

It is an amenable number.

13324405133021 is a deficient number, since it is larger than the sum of its proper divisors (81744816931).

13324405133021 is an equidigital number, since it uses as much as digits as its factorization.

13324405133021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81744816930.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 13324405133021 its reverse (12033150442331), we get a palindrome (25357555575352).

The spelling of 13324405133021 in words is "thirteen trillion, three hundred twenty-four billion, four hundred five million, one hundred thirty-three thousand, twenty-one".