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13324412124134 = 26662206062067
BaseRepresentation
bin1100000111100101010011…
…0110011111101111100110
31202011210122012010221202022
43001321110312133233212
53221301344000433014
644201052254143142
72543441232223436
oct301712466375746
952153565127668
1013324412124134
1142779403061a1
1215b243a7b1ab2
137586432ab297
14340c954022c6
151818ea0e2a8e
hexc1e54d9fbe6

13324412124134 has 4 divisors (see below), whose sum is σ = 19986618186204. Its totient is φ = 6662206062066.

The previous prime is 13324412124119. The next prime is 13324412124203. The reversal of 13324412124134 is 43142121442331.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13324412124094 and 13324412124103.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3331103031032 + ... + 3331103031035.

It is an arithmetic number, because the mean of its divisors is an integer number (4996654546551).

Almost surely, 213324412124134 is an apocalyptic number.

13324412124134 is a deficient number, since it is larger than the sum of its proper divisors (6662206062070).

13324412124134 is an equidigital number, since it uses as much as digits as its factorization.

13324412124134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6662206062069.

The product of its digits is 55296, while the sum is 35.

Adding to 13324412124134 its reverse (43142121442331), we get a palindrome (56466533566465).

The spelling of 13324412124134 in words is "thirteen trillion, three hundred twenty-four billion, four hundred twelve million, one hundred twenty-four thousand, one hundred thirty-four".

Divisors: 1 2 6662206062067 13324412124134