Base | Representation |
---|---|
bin | 1100000111100101011000… |
… | …0110100100010011101000 |
3 | 1202011210200122122100220111 |
4 | 3001321112012210103220 |
5 | 3221301414334124334 |
6 | 44201054324104104 |
7 | 2543441605515412 |
oct | 301712606442350 |
9 | 52153618570814 |
10 | 13324433114344 |
11 | 4277951142480 |
12 | 15b2445835034 |
13 | 75864774a321 |
14 | 340c981079b2 |
15 | 1818ebd8c064 |
hex | c1e561a44e8 |
13324433114344 has 32 divisors (see below), whose sum is σ = 27259356513600. Its totient is φ = 6055486232320.
The previous prime is 13324433114329. The next prime is 13324433114357. The reversal of 13324433114344 is 44341133442331.
It is a junction number, because it is equal to n+sod(n) for n = 13324433114297 and 13324433114306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12929377 + ... + 13921840.
It is an arithmetic number, because the mean of its divisors is an integer number (851854891050).
Almost surely, 213324433114344 is an apocalyptic number.
It is an amenable number.
13324433114344 is an abundant number, since it is smaller than the sum of its proper divisors (13934923399256).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13324433114344 is a wasteful number, since it uses less digits than its factorization.
13324433114344 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26856873 (or 26856869 counting only the distinct ones).
The product of its digits is 497664, while the sum is 40.
Adding to 13324433114344 its reverse (44341133442331), we get a palindrome (57665566556675).
The spelling of 13324433114344 in words is "thirteen trillion, three hundred twenty-four billion, four hundred thirty-three million, one hundred fourteen thousand, three hundred forty-four".
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