Base | Representation |
---|---|
bin | 1100000111100101110000… |
… | …1000101011111101111001 |
3 | 1202011210221201002211012220 |
4 | 3001321130020223331321 |
5 | 3221302121242131210 |
6 | 44201112341354253 |
7 | 2543444245045416 |
oct | 301713410537571 |
9 | 52153851084186 |
10 | 13324534333305 |
11 | 42779a3296808 |
12 | 15b2473708989 |
13 | 7586626c98c0 |
14 | 340ca773510d |
15 | 181905bd2c70 |
hex | c1e5c22bf79 |
13324534333305 has 32 divisors (see below), whose sum is σ = 23024237959296. Its totient is φ = 6541187794944.
The previous prime is 13324534333291. The next prime is 13324534333337. The reversal of 13324534333305 is 50333343542331.
It is not a de Polignac number, because 13324534333305 - 215 = 13324534300537 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 96717207 + ... + 96854876.
It is an arithmetic number, because the mean of its divisors is an integer number (719507436228).
Almost surely, 213324534333305 is an apocalyptic number.
13324534333305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13324534333305 is a deficient number, since it is larger than the sum of its proper divisors (9699703625991).
13324534333305 is a wasteful number, since it uses less digits than its factorization.
13324534333305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 193572457.
The product of its (nonzero) digits is 1749600, while the sum is 42.
Adding to 13324534333305 its reverse (50333343542331), we get a palindrome (63657877875636).
The spelling of 13324534333305 in words is "thirteen trillion, three hundred twenty-four billion, five hundred thirty-four million, three hundred thirty-three thousand, three hundred five".
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