Base | Representation |
---|---|
bin | 1100000111101000011011… |
… | …0010101111101010001111 |
3 | 1202011212210120202112111020 |
4 | 3001322012302233222033 |
5 | 3221310103000022201 |
6 | 44201311344525223 |
7 | 2543501055114645 |
oct | 301720662575217 |
9 | 52155716675436 |
10 | 13325250001551 |
11 | 4278230267974 |
12 | 15b2633320813 |
13 | 758747a63837 |
14 | 340d347cb195 |
15 | 18194894ca36 |
hex | c1e86cafa8f |
13325250001551 has 4 divisors (see below), whose sum is σ = 17767000002072. Its totient is φ = 8883500001032.
The previous prime is 13325250001507. The next prime is 13325250001589. The reversal of 13325250001551 is 15510005252331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13325250001551 - 27 = 13325250001423 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13325250001351) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2220875000256 + ... + 2220875000261.
It is an arithmetic number, because the mean of its divisors is an integer number (4441750000518).
Almost surely, 213325250001551 is an apocalyptic number.
13325250001551 is a deficient number, since it is larger than the sum of its proper divisors (4441750000521).
13325250001551 is an equidigital number, since it uses as much as digits as its factorization.
13325250001551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4441750000520.
The product of its (nonzero) digits is 22500, while the sum is 33.
Adding to 13325250001551 its reverse (15510005252331), we get a palindrome (28835255253882).
The spelling of 13325250001551 in words is "thirteen trillion, three hundred twenty-five billion, two hundred fifty million, one thousand, five hundred fifty-one".
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