Base | Representation |
---|---|
bin | 111110000011001111… |
… | …0110010100101000111 |
3 | 110201221121111120221202 |
4 | 1330012132302211013 |
5 | 4140400144032332 |
6 | 141114312133115 |
7 | 12425061303602 |
oct | 1740636624507 |
9 | 421847446852 |
10 | 133252720967 |
11 | 5156a761583 |
12 | 219aa09719b |
13 | c747a420b2 |
14 | 6641499339 |
15 | 36ed6c7a62 |
hex | 1f067b2947 |
133252720967 has 8 divisors (see below), whose sum is σ = 144904390416. Its totient is φ = 122024748672.
The previous prime is 133252720897. The next prime is 133252720981. The reversal of 133252720967 is 769027252331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133252720967 is a prime.
It is a super-2 number, since 2×1332527209672 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133252720987) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 105923633 + ... + 105924890.
It is an arithmetic number, because the mean of its divisors is an integer number (18113048802).
Almost surely, 2133252720967 is an apocalyptic number.
133252720967 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
133252720967 is a deficient number, since it is larger than the sum of its proper divisors (11651669449).
133252720967 is a wasteful number, since it uses less digits than its factorization.
133252720967 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211848577.
The product of its (nonzero) digits is 952560, while the sum is 47.
The spelling of 133252720967 in words is "one hundred thirty-three billion, two hundred fifty-two million, seven hundred twenty thousand, nine hundred sixty-seven".
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