Base | Representation |
---|---|
bin | 10011011001000001010… |
… | …010100010111101101001 |
3 | 11201101111200011000122101 |
4 | 103121001102202331221 |
5 | 133313013010230401 |
6 | 2500054102453401 |
7 | 165162315451153 |
oct | 23310122427551 |
9 | 4641450130571 |
10 | 1332535242601 |
11 | 474141450542 |
12 | 196307434261 |
13 | 988717aac94 |
14 | 486d05b9ad3 |
15 | 249e03dc101 |
hex | 136414a2f69 |
1332535242601 has 2 divisors, whose sum is σ = 1332535242602. Its totient is φ = 1332535242600.
The previous prime is 1332535242593. The next prime is 1332535242607. The reversal of 1332535242601 is 1062425352331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1266615193600 + 65920049001 = 1125440^2 + 256749^2 .
It is a cyclic number.
It is not a de Polignac number, because 1332535242601 - 23 = 1332535242593 is a prime.
It is not a weakly prime, because it can be changed into another prime (1332535242607) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666267621300 + 666267621301.
It is an arithmetic number, because the mean of its divisors is an integer number (666267621301).
Almost surely, 21332535242601 is an apocalyptic number.
It is an amenable number.
1332535242601 is a deficient number, since it is larger than the sum of its proper divisors (1).
1332535242601 is an equidigital number, since it uses as much as digits as its factorization.
1332535242601 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 37.
The spelling of 1332535242601 in words is "one trillion, three hundred thirty-two billion, five hundred thirty-five million, two hundred forty-two thousand, six hundred one".
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