Base | Representation |
---|---|
bin | 1100000111101001000000… |
… | …0010011010100000110001 |
3 | 1202011220012101121120021221 |
4 | 3001322100002122200301 |
5 | 3221310412201313202 |
6 | 44201335005145041 |
7 | 2543504650346125 |
oct | 301722002324061 |
9 | 52156171546257 |
10 | 13325405104177 |
11 | 42782aa874861 |
12 | 15b267725b181 |
13 | 758770c2b13a |
14 | 340d4b243585 |
15 | 181957389037 |
hex | c1e9009a831 |
13325405104177 has 2 divisors, whose sum is σ = 13325405104178. Its totient is φ = 13325405104176.
The previous prime is 13325405104171. The next prime is 13325405104261. The reversal of 13325405104177 is 77140150452331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10044582923761 + 3280822180416 = 3169319^2 + 1811304^2 .
It is a cyclic number.
It is not a de Polignac number, because 13325405104177 - 227 = 13325270886449 is a prime.
It is not a weakly prime, because it can be changed into another prime (13325405104171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662702552088 + 6662702552089.
It is an arithmetic number, because the mean of its divisors is an integer number (6662702552089).
Almost surely, 213325405104177 is an apocalyptic number.
It is an amenable number.
13325405104177 is a deficient number, since it is larger than the sum of its proper divisors (1).
13325405104177 is an equidigital number, since it uses as much as digits as its factorization.
13325405104177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 352800, while the sum is 43.
The spelling of 13325405104177 in words is "thirteen trillion, three hundred twenty-five billion, four hundred five million, one hundred four thousand, one hundred seventy-seven".
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