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13325405104234 = 26662702552117
BaseRepresentation
bin1100000111101001000000…
…0010011010100001101010
31202011220012101121120101001
43001322100002122201222
53221310412201313414
644201335005145214
72543504650346236
oct301722002324152
952156171546331
1013325405104234
1142782aa874903
1215b267725b20a
13758770c2b182
14340d4b2435c6
15181957389074
hexc1e9009a86a

13325405104234 has 4 divisors (see below), whose sum is σ = 19988107656354. Its totient is φ = 6662702552116.

The previous prime is 13325405104177. The next prime is 13325405104261. The reversal of 13325405104234 is 43240150452331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10046028185209 + 3279376919025 = 3169547^2 + 1810905^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13325405104193 and 13325405104202.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3331351276057 + ... + 3331351276060.

Almost surely, 213325405104234 is an apocalyptic number.

13325405104234 is a deficient number, since it is larger than the sum of its proper divisors (6662702552120).

13325405104234 is an equidigital number, since it uses as much as digits as its factorization.

13325405104234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6662702552119.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 13325405104234 its reverse (43240150452331), we get a palindrome (56565555556565).

The spelling of 13325405104234 in words is "thirteen trillion, three hundred twenty-five billion, four hundred five million, one hundred four thousand, two hundred thirty-four".

Divisors: 1 2 6662702552117 13325405104234