Base | Representation |
---|---|
bin | 1100000111101001100001… |
… | …1100100000001110011011 |
3 | 1202011220120020000222221121 |
4 | 3001322120130200032123 |
5 | 3221311204304123201 |
6 | 44201401004350111 |
7 | 2543511312330505 |
oct | 301723034401633 |
9 | 52156506028847 |
10 | 13325546161051 |
11 | 4278372458993 |
12 | 15b26b6545337 |
13 | 758794218547 |
14 | 340d61c80d75 |
15 | 18196494d9a1 |
hex | c1e9872039b |
13325546161051 has 2 divisors, whose sum is σ = 13325546161052. Its totient is φ = 13325546161050.
The previous prime is 13325546161013. The next prime is 13325546161063. The reversal of 13325546161051 is 15016164552331.
It is a strong prime.
It is an emirp because it is prime and its reverse (15016164552331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13325546161051 - 27 = 13325546160923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13325546160989 and 13325546161007.
It is not a weakly prime, because it can be changed into another prime (13325546161651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662773080525 + 6662773080526.
It is an arithmetic number, because the mean of its divisors is an integer number (6662773080526).
Almost surely, 213325546161051 is an apocalyptic number.
13325546161051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13325546161051 is an equidigital number, since it uses as much as digits as its factorization.
13325546161051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 43.
The spelling of 13325546161051 in words is "thirteen trillion, three hundred twenty-five billion, five hundred forty-six million, one hundred sixty-one thousand, fifty-one".
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