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1333001120131 is a prime number
BaseRepresentation
bin10011011001011101000…
…011101110100110000011
311201102201010210001110201
4103121131003232212003
5133314441241321011
62500212224110031
7165210003366532
oct23313503564603
94642633701421
101333001120131
1147436042119a
12196417465317
1398917176865
144873640c319
1524a1b264cc1
hex1365d0ee983

1333001120131 has 2 divisors, whose sum is σ = 1333001120132. Its totient is φ = 1333001120130.

The previous prime is 1333001120111. The next prime is 1333001120177. The reversal of 1333001120131 is 1310211003331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1333001120131 - 217 = 1333000989059 is a prime.

It is a super-2 number, since 2×13330011201312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1333001120099 and 1333001120108.

It is not a weakly prime, because it can be changed into another prime (1333001120111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666500560065 + 666500560066.

It is an arithmetic number, because the mean of its divisors is an integer number (666500560066).

Almost surely, 21333001120131 is an apocalyptic number.

1333001120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333001120131 is an equidigital number, since it uses as much as digits as its factorization.

1333001120131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1333001120131 its reverse (1310211003331), we get a palindrome (2643212123462).

The spelling of 1333001120131 in words is "one trillion, three hundred thirty-three billion, one million, one hundred twenty thousand, one hundred thirty-one".