Base | Representation |
---|---|
bin | 1111111000111… |
… | …11111110011001 |
3 | 100021211100101112 |
4 | 13330133332121 |
5 | 233111100441 |
6 | 21121030105 |
7 | 3206014043 |
oct | 774377631 |
9 | 307740345 |
10 | 133300121 |
11 | 69276399 |
12 | 38785335 |
13 | 21802916 |
14 | 139bca93 |
15 | ba814eb |
hex | 7f1ff99 |
133300121 has 2 divisors, whose sum is σ = 133300122. Its totient is φ = 133300120.
The previous prime is 133300091. The next prime is 133300147. The reversal of 133300121 is 121003331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 74563225 + 58736896 = 8635^2 + 7664^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133300121 is a prime.
It is a super-2 number, since 2×1333001212 = 35537844517229282, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 133300096 and 133300105.
It is not a weakly prime, because it can be changed into another prime (133300151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66650060 + 66650061.
It is an arithmetic number, because the mean of its divisors is an integer number (66650061).
Almost surely, 2133300121 is an apocalyptic number.
It is an amenable number.
133300121 is a deficient number, since it is larger than the sum of its proper divisors (1).
133300121 is an equidigital number, since it uses as much as digits as its factorization.
133300121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
The square root of 133300121 is about 11545.5671580048. The cubic root of 133300121 is about 510.8305331994.
Adding to 133300121 its reverse (121003331), we get a palindrome (254303452).
The spelling of 133300121 in words is "one hundred thirty-three million, three hundred thousand, one hundred twenty-one".
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