Base | Representation |
---|---|
bin | 1100000111111010001100… |
… | …0110111001010100010101 |
3 | 1202012100010000101020112021 |
4 | 3001332203012321110111 |
5 | 3221344340110411313 |
6 | 44203420542453141 |
7 | 2544030215415562 |
oct | 301764306712425 |
9 | 52170100336467 |
10 | 13330020013333 |
11 | 427a25886a371 |
12 | 15b35448941b1 |
13 | 75902806860a |
14 | 341268101869 |
15 | 181b275c478d |
hex | c1fa31b9515 |
13330020013333 has 4 divisors (see below), whose sum is σ = 13332861633888. Its totient is φ = 13327178392780.
The previous prime is 13330020013301. The next prime is 13330020013339. The reversal of 13330020013333 is 33331002003331.
13330020013333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13330020013333 - 25 = 13330020013301 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13330020013298 and 13330020013307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13330020013339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1420803241 + ... + 1420812622.
It is an arithmetic number, because the mean of its divisors is an integer number (3333215408472).
Almost surely, 213330020013333 is an apocalyptic number.
It is an amenable number.
13330020013333 is a deficient number, since it is larger than the sum of its proper divisors (2841620555).
13330020013333 is an equidigital number, since it uses as much as digits as its factorization.
13330020013333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2841620554.
The product of its (nonzero) digits is 4374, while the sum is 25.
Adding to 13330020013333 its reverse (33331002003331), we get a palindrome (46661022016664).
The spelling of 13330020013333 in words is "thirteen trillion, three hundred thirty billion, twenty million, thirteen thousand, three hundred thirty-three".
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