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13330060323907 is a prime number
BaseRepresentation
bin1100000111111010010110…
…0000101010110001000011
31202012100012211020020020111
43001332211200222301003
53221344430420331112
644203424542452151
72544031215146245
oct301764540526103
952170184206214
1013330060323907
11427a2795a2298
1215b3556294057
13759033510622
1434126d5d6095
15181b2add85a7
hexc1fa582ac43

13330060323907 has 2 divisors, whose sum is σ = 13330060323908. Its totient is φ = 13330060323906.

The previous prime is 13330060323829. The next prime is 13330060323971. The reversal of 13330060323907 is 70932306003331.

It is a strong prime.

It is an emirp because it is prime and its reverse (70932306003331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13330060323907 - 211 = 13330060321859 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13330060323907.

It is not a weakly prime, because it can be changed into another prime (13330060326907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665030161953 + 6665030161954.

It is an arithmetic number, because the mean of its divisors is an integer number (6665030161954).

Almost surely, 213330060323907 is an apocalyptic number.

13330060323907 is a deficient number, since it is larger than the sum of its proper divisors (1).

13330060323907 is an equidigital number, since it uses as much as digits as its factorization.

13330060323907 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 183708, while the sum is 40.

The spelling of 13330060323907 in words is "thirteen trillion, three hundred thirty billion, sixty million, three hundred twenty-three thousand, nine hundred seven".