Base | Representation |
---|---|
bin | 10011011001011101110… |
… | …001011011110111011001 |
3 | 11201102201222022210120011 |
4 | 103121131301123313121 |
5 | 133320002323231131 |
6 | 2500213333001521 |
7 | 165210210262315 |
oct | 23313561336731 |
9 | 4642658283504 |
10 | 1333013102041 |
11 | 4743671653a5 |
12 | 19641b4832a1 |
13 | 989197b054a |
14 | 48737c4ab45 |
15 | 24a1c3300b1 |
hex | 1365dc5bdd9 |
1333013102041 has 2 divisors, whose sum is σ = 1333013102042. Its totient is φ = 1333013102040.
The previous prime is 1333013102027. The next prime is 1333013102053. The reversal of 1333013102041 is 1402013103331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1268698113225 + 64314988816 = 1126365^2 + 253604^2 .
It is a cyclic number.
It is not a de Polignac number, because 1333013102041 - 25 = 1333013102009 is a prime.
It is not a weakly prime, because it can be changed into another prime (1333013109041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666506551020 + 666506551021.
It is an arithmetic number, because the mean of its divisors is an integer number (666506551021).
Almost surely, 21333013102041 is an apocalyptic number.
It is an amenable number.
1333013102041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333013102041 is an equidigital number, since it uses as much as digits as its factorization.
1333013102041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1333013102041 its reverse (1402013103331), we get a palindrome (2735026205372).
The spelling of 1333013102041 in words is "one trillion, three hundred thirty-three billion, thirteen million, one hundred two thousand, forty-one".
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