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13330201524041 is a prime number
BaseRepresentation
bin1100000111111010110111…
…1011010011011101001001
31202012100120122220221102002
43001332231323103131021
53221400223042232131
644203450545120345
72544034551265403
oct301765573233511
952170518827362
1013330201524041
11427a341274016
1215b35956290b5
1375905684acbc
1434128426db73
15181b384ca6cb
hexc1faded3749

13330201524041 has 2 divisors, whose sum is σ = 13330201524042. Its totient is φ = 13330201524040.

The previous prime is 13330201524011. The next prime is 13330201524077. The reversal of 13330201524041 is 14042510203331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10951731235600 + 2378470288441 = 3309340^2 + 1542229^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13330201524041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13330201523995 and 13330201524013.

It is not a weakly prime, because it can be changed into another prime (13330201524011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665100762020 + 6665100762021.

It is an arithmetic number, because the mean of its divisors is an integer number (6665100762021).

Almost surely, 213330201524041 is an apocalyptic number.

It is an amenable number.

13330201524041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13330201524041 is an equidigital number, since it uses as much as digits as its factorization.

13330201524041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 13330201524041 its reverse (14042510203331), we get a palindrome (27372711727372).

The spelling of 13330201524041 in words is "thirteen trillion, three hundred thirty billion, two hundred one million, five hundred twenty-four thousand, forty-one".