Base | Representation |
---|---|
bin | 111110000100101101… |
… | …1100010011100111011 |
3 | 110202002001121101121002 |
4 | 1330021123202130323 |
5 | 4141000330400443 |
6 | 141123240435215 |
7 | 12426232001651 |
oct | 1741133423473 |
9 | 422061541532 |
10 | 133302200123 |
11 | 51595686a44 |
12 | 21a02778b0b |
13 | c7550773c1 |
14 | 6647c98dd1 |
15 | 3702bed2b8 |
hex | 1f096e273b |
133302200123 has 2 divisors, whose sum is σ = 133302200124. Its totient is φ = 133302200122.
The previous prime is 133302200099. The next prime is 133302200183. The reversal of 133302200123 is 321002203331.
It is a weak prime.
It is an emirp because it is prime and its reverse (321002203331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133302200123 - 210 = 133302199099 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133302200095 and 133302200104.
It is not a weakly prime, because it can be changed into another prime (133302200183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66651100061 + 66651100062.
It is an arithmetic number, because the mean of its divisors is an integer number (66651100062).
Almost surely, 2133302200123 is an apocalyptic number.
133302200123 is a deficient number, since it is larger than the sum of its proper divisors (1).
133302200123 is an equidigital number, since it uses as much as digits as its factorization.
133302200123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 133302200123 its reverse (321002203331), we get a palindrome (454304403454).
The spelling of 133302200123 in words is "one hundred thirty-three billion, three hundred two million, two hundred thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •