Base | Representation |
---|---|
bin | 11000110101000101… |
… | …11000001010100111 |
3 | 1021102000012222122220 |
4 | 30122202320022213 |
5 | 204300021034310 |
6 | 10042425323423 |
7 | 651223163532 |
oct | 143242701247 |
9 | 37360188586 |
10 | 13330252455 |
11 | 5720641a73 |
12 | 2700336573 |
13 | 1345932660 |
14 | 906575a19 |
15 | 530439670 |
hex | 31a8b82a7 |
13330252455 has 32 divisors (see below), whose sum is σ = 23024010240. Its totient is φ = 6546883200.
The previous prime is 13330252447. The next prime is 13330252459. The reversal of 13330252455 is 55425203331.
It is not a de Polignac number, because 13330252455 - 23 = 13330252447 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13330252459) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 130 + ... + 163280.
It is an arithmetic number, because the mean of its divisors is an integer number (719500320).
Almost surely, 213330252455 is an apocalyptic number.
13330252455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13330252455 is a deficient number, since it is larger than the sum of its proper divisors (9693757785).
13330252455 is a wasteful number, since it uses less digits than its factorization.
13330252455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163591.
The product of its (nonzero) digits is 54000, while the sum is 33.
Adding to 13330252455 its reverse (55425203331), we get a palindrome (68755455786).
The spelling of 13330252455 in words is "thirteen billion, three hundred thirty million, two hundred fifty-two thousand, four hundred fifty-five".
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