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13331031214211 is a prime number
BaseRepresentation
bin1100000111111101111101…
…1000010100100010000011
31202012102201111010120100122
43001333133120110202003
53221403422442323321
644204105144210455
72544064244450234
oct301773730244203
952172644116318
1013331031214211
11427a727643577
1215b3787469a2b
137591596c7b29
1434132252708b
15181b862698ab
hexc1fdf614883

13331031214211 has 2 divisors, whose sum is σ = 13331031214212. Its totient is φ = 13331031214210.

The previous prime is 13331031214183. The next prime is 13331031214231. The reversal of 13331031214211 is 11241213013331.

13331031214211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13331031214211 - 218 = 13331030952067 is a prime.

It is not a weakly prime, because it can be changed into another prime (13331031214231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665515607105 + 6665515607106.

It is an arithmetic number, because the mean of its divisors is an integer number (6665515607106).

Almost surely, 213331031214211 is an apocalyptic number.

13331031214211 is a deficient number, since it is larger than the sum of its proper divisors (1).

13331031214211 is an equidigital number, since it uses as much as digits as its factorization.

13331031214211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 26.

Adding to 13331031214211 its reverse (11241213013331), we get a palindrome (24572244227542).

The spelling of 13331031214211 in words is "thirteen trillion, three hundred thirty-one billion, thirty-one million, two hundred fourteen thousand, two hundred eleven".