Base | Representation |
---|---|
bin | 1100000111111101111111… |
… | …1111001110011110001001 |
3 | 1202012102202012022201110121 |
4 | 3001333133333032132021 |
5 | 3221403433100204001 |
6 | 44204110150543241 |
7 | 2544064430235304 |
oct | 301773777163611 |
9 | 52172665281417 |
10 | 13331041413001 |
11 | 427a73237a024 |
12 | 15b378a967b21 |
13 | 75915b859010 |
14 | 341323a1db3b |
15 | 181b870d16a1 |
hex | c1fdffce789 |
13331041413001 has 64 divisors (see below), whose sum is σ = 15521106585600. Its totient is φ = 11344511033856.
The previous prime is 13331041412959. The next prime is 13331041413113. The reversal of 13331041413001 is 10031414013331.
It is not a de Polignac number, because 13331041413001 - 227 = 13330907195273 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13331041413601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3584575020 + ... + 3584578738.
It is an arithmetic number, because the mean of its divisors is an integer number (242517290400).
Almost surely, 213331041413001 is an apocalyptic number.
It is an amenable number.
13331041413001 is a deficient number, since it is larger than the sum of its proper divisors (2190065172599).
13331041413001 is a wasteful number, since it uses less digits than its factorization.
13331041413001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4958.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13331041413001 its reverse (10031414013331), we get a palindrome (23362455426332).
The spelling of 13331041413001 in words is "thirteen trillion, three hundred thirty-one billion, forty-one million, four hundred thirteen thousand, one".
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