Base | Representation |
---|---|
bin | 11110010011111100100000… |
… | …010000100011111110010111 |
3 | 122111000111122122212110110221 |
4 | 132103330200100203332113 |
5 | 114433141014431104421 |
6 | 1151310411315055211 |
7 | 40036322256520564 |
oct | 3623744020437627 |
9 | 574014578773427 |
10 | 133312031113111 |
11 | 39528351142594 |
12 | 12b509215a1507 |
13 | 5950369650016 |
14 | 24cc49ddd386b |
15 | 1062b42815841 |
hex | 793f20423f97 |
133312031113111 has 8 divisors (see below), whose sum is σ = 133391026969200. Its totient is φ = 133233058649088.
The previous prime is 133312031113099. The next prime is 133312031113127. The reversal of 133312031113111 is 111311130213331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133312031113111 - 213 = 133312031104919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133312031113181) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5560005 + ... + 17249281.
It is an arithmetic number, because the mean of its divisors is an integer number (16673878371150).
Almost surely, 2133312031113111 is an apocalyptic number.
133312031113111 is a deficient number, since it is larger than the sum of its proper divisors (78995856089).
133312031113111 is a wasteful number, since it uses less digits than its factorization.
133312031113111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11696033.
The product of its (nonzero) digits is 486, while the sum is 25.
Adding to 133312031113111 its reverse (111311130213331), we get a palindrome (244623161326442).
The spelling of 133312031113111 in words is "one hundred thirty-three trillion, three hundred twelve billion, thirty-one million, one hundred thirteen thousand, one hundred eleven".
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