13331210413442 has 4 divisors (see below), whose sum is σ = 19996815620166. Its totient is φ = 6665605206720.

The previous prime is 13331210413387. The next prime is 13331210413471. The reversal of 13331210413442 is 24431401213331.

13331210413442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 10951870228321 + 2379340185121 = 3309361^2 + 1542511^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13331210413399 and 13331210413408.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3332802603359 + ... + 3332802603362.

Almost surely, 2^{13331210413442} is an apocalyptic number.

13331210413442 is a deficient number, since it is larger than the sum of its proper divisors (6665605206724).

13331210413442 is an equidigital number, since it uses as much as digits as its factorization.

13331210413442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6665605206723.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 13331210413442 its reverse (24431401213331), we get a palindrome (37762611626773).

The spelling of 13331210413442 in words is "thirteen trillion, three hundred thirty-one billion, two hundred ten million, four hundred thirteen thousand, four hundred forty-two".