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133312130003333 = 612185444754153
BaseRepresentation
bin11110010011111100100110…
…001001110011000110000101
3122111000111220112221121100202
4132103330212021303012011
5114433141220240101313
61151310425210420245
740036324600211351
oct3623744611630605
9574014815847322
10133312130003333
11395283a1a46246
1212b5094a731685
135950383c95648
1424cc4ad1b6461
151062b4b34b558
hex793f26273185

133312130003333 has 4 divisors (see below), whose sum is σ = 135497574757548. Its totient is φ = 131126685249120.

The previous prime is 133312130003231. The next prime is 133312130003357. The reversal of 133312130003333 is 333300031213331.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1614632745124 + 131697497258209 = 1270682^2 + 11475953^2 .

It is a cyclic number.

It is not a de Polignac number, because 133312130003333 - 220 = 133312128954757 is a prime.

It is a super-2 number, since 2×1333121300033332 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133312130003296 and 133312130003305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133312130003033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1092722377016 + ... + 1092722377137.

It is an arithmetic number, because the mean of its divisors is an integer number (33874393689387).

Almost surely, 2133312130003333 is an apocalyptic number.

It is an amenable number.

133312130003333 is a deficient number, since it is larger than the sum of its proper divisors (2185444754215).

133312130003333 is an equidigital number, since it uses as much as digits as its factorization.

133312130003333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2185444754214.

The product of its (nonzero) digits is 13122, while the sum is 29.

Adding to 133312130003333 its reverse (333300031213331), we get a palindrome (466612161216664).

The spelling of 133312130003333 in words is "one hundred thirty-three trillion, three hundred twelve billion, one hundred thirty million, three thousand, three hundred thirty-three".

Divisors: 1 61 2185444754153 133312130003333