Base | Representation |
---|---|
bin | 10011011001100100101… |
… | …111101111110110100100 |
3 | 11201110001010110220202210 |
4 | 103121210233233312210 |
5 | 133320222301201012 |
6 | 2500233112403420 |
7 | 165213130611525 |
oct | 23314457576644 |
9 | 4643033426683 |
10 | 1333130100132 |
11 | 474417206836 |
12 | 1964526a6570 |
13 | 98937ac5c9c |
14 | 487495c484c |
15 | 24a2774123c |
hex | 13664befda4 |
1333130100132 has 24 divisors (see below), whose sum is σ = 3124585950976. Its totient is φ = 442383978528.
The previous prime is 1333130100131. The next prime is 1333130100151. The reversal of 1333130100132 is 2310010313331.
It is a junction number, because it is equal to n+sod(n) for n = 1333130100099 and 1333130100108.
It is not an unprimeable number, because it can be changed into a prime (1333130100131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 249087403 + ... + 249092754.
Almost surely, 21333130100132 is an apocalyptic number.
1333130100132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1333130100132 is an abundant number, since it is smaller than the sum of its proper divisors (1791455850844).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1333130100132 is a wasteful number, since it uses less digits than its factorization.
1333130100132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 498180387 (or 498180385 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 1333130100132 its reverse (2310010313331), we get a palindrome (3643140413463).
The spelling of 1333130100132 in words is "one trillion, three hundred thirty-three billion, one hundred thirty million, one hundred thousand, one hundred thirty-two".
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