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1333130104121 is a prime number
BaseRepresentation
bin10011011001100100101…
…111110000110100111001
311201110001010111010020112
4103121210233300310321
5133320222301312441
62500233112434105
7165213130626254
oct23314457606471
94643033433215
101333130104121
11474417209832
121964526a8935
1398937ac7a4a
14487495c609b
1524a277424eb
hex13664bf0d39

1333130104121 has 2 divisors, whose sum is σ = 1333130104122. Its totient is φ = 1333130104120.

The previous prime is 1333130104093. The next prime is 1333130104157. The reversal of 1333130104121 is 1214010313331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 937916708521 + 395213395600 = 968461^2 + 628660^2 .

It is a cyclic number.

It is not a de Polignac number, because 1333130104121 - 218 = 1333129841977 is a prime.

It is not a weakly prime, because it can be changed into another prime (1333130104721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666565052060 + 666565052061.

It is an arithmetic number, because the mean of its divisors is an integer number (666565052061).

Almost surely, 21333130104121 is an apocalyptic number.

It is an amenable number.

1333130104121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333130104121 is an equidigital number, since it uses as much as digits as its factorization.

1333130104121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1333130104121 its reverse (1214010313331), we get a palindrome (2547140417452).

The spelling of 1333130104121 in words is "one trillion, three hundred thirty-three billion, one hundred thirty million, one hundred four thousand, one hundred twenty-one".