Base | Representation |
---|---|
bin | 10011011001100100101… |
… | …111110000110100111001 |
3 | 11201110001010111010020112 |
4 | 103121210233300310321 |
5 | 133320222301312441 |
6 | 2500233112434105 |
7 | 165213130626254 |
oct | 23314457606471 |
9 | 4643033433215 |
10 | 1333130104121 |
11 | 474417209832 |
12 | 1964526a8935 |
13 | 98937ac7a4a |
14 | 487495c609b |
15 | 24a277424eb |
hex | 13664bf0d39 |
1333130104121 has 2 divisors, whose sum is σ = 1333130104122. Its totient is φ = 1333130104120.
The previous prime is 1333130104093. The next prime is 1333130104157. The reversal of 1333130104121 is 1214010313331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 937916708521 + 395213395600 = 968461^2 + 628660^2 .
It is a cyclic number.
It is not a de Polignac number, because 1333130104121 - 218 = 1333129841977 is a prime.
It is not a weakly prime, because it can be changed into another prime (1333130104721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666565052060 + 666565052061.
It is an arithmetic number, because the mean of its divisors is an integer number (666565052061).
Almost surely, 21333130104121 is an apocalyptic number.
It is an amenable number.
1333130104121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333130104121 is an equidigital number, since it uses as much as digits as its factorization.
1333130104121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1333130104121 its reverse (1214010313331), we get a palindrome (2547140417452).
The spelling of 1333130104121 in words is "one trillion, three hundred thirty-three billion, one hundred thirty million, one hundred four thousand, one hundred twenty-one".
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