13331310041131 has 4 divisors (see below), whose sum is σ = 13331358823264. Its totient is φ = 13331261259000.

The previous prime is 13331310041099. The next prime is 13331310041141. The reversal of 13331310041131 is 13114001313331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13331310041131 - 2⁵ = 13331310041099 is a prime.

It is a super-2 number, since 2×13331310041131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13331310041096 and 13331310041105.

It is not an unprimeable number, because it can be changed into a prime (13331310041141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23978820 + ... + 24528481.

It is an arithmetic number, because the mean of its divisors is an integer number (3332839705816).

Almost surely, 2^{13331310041131} is an apocalyptic number.

13331310041131 is a deficient number, since it is larger than the sum of its proper divisors (48782133).

13331310041131 is an equidigital number, since it uses as much as digits as its factorization.

13331310041131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48782132.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13331310041131 its reverse (13114001313331), we get a palindrome (26445311354462).

The spelling of 13331310041131 in words is "thirteen trillion, three hundred thirty-one billion, three hundred ten million, forty-one thousand, one hundred thirty-one".