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1333201200113 is a prime number
BaseRepresentation
bin10011011001101000111…
…110111110001111110001
311201110020002021011121102
4103121220332332033301
5133320344001400423
62500244132334145
7165214653136226
oct23315076761761
94643202234542
101333201200113
11474453359252
12196472474355
139894975b393
1448754c1194d
1524a2dad7c28
hex13668fbe3f1

1333201200113 has 2 divisors, whose sum is σ = 1333201200114. Its totient is φ = 1333201200112.

The previous prime is 1333201200109. The next prime is 1333201200167. The reversal of 1333201200113 is 3110021023331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1241069525089 + 92131675024 = 1114033^2 + 303532^2 .

It is an emirp because it is prime and its reverse (3110021023331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1333201200113 - 22 = 1333201200109 is a prime.

It is not a weakly prime, because it can be changed into another prime (1333201200103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666600600056 + 666600600057.

It is an arithmetic number, because the mean of its divisors is an integer number (666600600057).

Almost surely, 21333201200113 is an apocalyptic number.

It is an amenable number.

1333201200113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333201200113 is an equidigital number, since it uses as much as digits as its factorization.

1333201200113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 1333201200113 its reverse (3110021023331), we get a palindrome (4443222223444).

The spelling of 1333201200113 in words is "one trillion, three hundred thirty-three billion, two hundred one million, two hundred thousand, one hundred thirteen".