Base | Representation |
---|---|
bin | 1100001000000001100111… |
… | …1010000010000101100011 |
3 | 1202012112020220210001201011 |
4 | 3002000121322002011203 |
5 | 3221412430330130313 |
6 | 44204350422121351 |
7 | 2544130466551564 |
oct | 302003172020543 |
9 | 52175226701634 |
10 | 13332013130083 |
11 | 428009093549a |
12 | 15b3a00280257 |
13 | 759284c7293b |
14 | 3413b6ac816b |
15 | 181be257793d |
hex | c2019e82163 |
13332013130083 has 2 divisors, whose sum is σ = 13332013130084. Its totient is φ = 13332013130082.
The previous prime is 13332013130069. The next prime is 13332013130087. The reversal of 13332013130083 is 38003131023331.
It is a strong prime.
It is an emirp because it is prime and its reverse (38003131023331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13332013130083 - 29 = 13332013129571 is a prime.
It is a super-2 number, since 2×133320131300832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13332013130087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666006565041 + 6666006565042.
It is an arithmetic number, because the mean of its divisors is an integer number (6666006565042).
Almost surely, 213332013130083 is an apocalyptic number.
13332013130083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332013130083 is an equidigital number, since it uses as much as digits as its factorization.
13332013130083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 31.
The spelling of 13332013130083 in words is "thirteen trillion, three hundred thirty-two billion, thirteen million, one hundred thirty thousand, eighty-three".
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