Base | Representation |
---|---|
bin | 11110010100000100000011… |
… | …010111101110000000011001 |
3 | 122111001021120112100220121221 |
4 | 132110010003113232000121 |
5 | 114433304114403301122 |
6 | 1151314231455132041 |
7 | 40040030156266534 |
oct | 3624040327560031 |
9 | 574037515326557 |
10 | 133320136384537 |
11 | 39530830381a13 |
12 | 12b52403b14021 |
13 | 595105b93110b |
14 | 24cca2c661a1b |
15 | 1062e691a76c7 |
hex | 7941035ee019 |
133320136384537 has 2 divisors, whose sum is σ = 133320136384538. Its totient is φ = 133320136384536.
The previous prime is 133320136384499. The next prime is 133320136384579. The reversal of 133320136384537 is 735483631023331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 105868027629961 + 27452108754576 = 10289219^2 + 5239476^2 .
It is a cyclic number.
It is not a de Polignac number, because 133320136384537 - 215 = 133320136351769 is a prime.
It is not a weakly prime, because it can be changed into another prime (133320136384637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66660068192268 + 66660068192269.
It is an arithmetic number, because the mean of its divisors is an integer number (66660068192269).
Almost surely, 2133320136384537 is an apocalyptic number.
It is an amenable number.
133320136384537 is a deficient number, since it is larger than the sum of its proper divisors (1).
133320136384537 is an equidigital number, since it uses as much as digits as its factorization.
133320136384537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9797760, while the sum is 52.
The spelling of 133320136384537 in words is "one hundred thirty-three trillion, three hundred twenty billion, one hundred thirty-six million, three hundred eighty-four thousand, five hundred thirty-seven".
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