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133320136384537 is a prime number
BaseRepresentation
bin11110010100000100000011…
…010111101110000000011001
3122111001021120112100220121221
4132110010003113232000121
5114433304114403301122
61151314231455132041
740040030156266534
oct3624040327560031
9574037515326557
10133320136384537
1139530830381a13
1212b52403b14021
13595105b93110b
1424cca2c661a1b
151062e691a76c7
hex7941035ee019

133320136384537 has 2 divisors, whose sum is σ = 133320136384538. Its totient is φ = 133320136384536.

The previous prime is 133320136384499. The next prime is 133320136384579. The reversal of 133320136384537 is 735483631023331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105868027629961 + 27452108754576 = 10289219^2 + 5239476^2 .

It is a cyclic number.

It is not a de Polignac number, because 133320136384537 - 215 = 133320136351769 is a prime.

It is not a weakly prime, because it can be changed into another prime (133320136384637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66660068192268 + 66660068192269.

It is an arithmetic number, because the mean of its divisors is an integer number (66660068192269).

Almost surely, 2133320136384537 is an apocalyptic number.

It is an amenable number.

133320136384537 is a deficient number, since it is larger than the sum of its proper divisors (1).

133320136384537 is an equidigital number, since it uses as much as digits as its factorization.

133320136384537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9797760, while the sum is 52.

The spelling of 133320136384537 in words is "one hundred thirty-three trillion, three hundred twenty billion, one hundred thirty-six million, three hundred eighty-four thousand, five hundred thirty-seven".