Base | Representation |
---|---|
bin | 11110010100000100000111… |
… | …110100101111110100100011 |
3 | 122111001021202201222000002211 |
4 | 132110010013310233310203 |
5 | 114433304243020244021 |
6 | 1151314243124422551 |
7 | 40040032054344622 |
oct | 3624040764576443 |
9 | 574037681860084 |
10 | 133320211103011 |
11 | 39530869576019 |
12 | 12b52424b47a57 |
13 | 595107126252a |
14 | 24cca385516b9 |
15 | 1062e70a163e1 |
hex | 794107d2fd23 |
133320211103011 has 2 divisors, whose sum is σ = 133320211103012. Its totient is φ = 133320211103010.
The previous prime is 133320211102987. The next prime is 133320211103039. The reversal of 133320211103011 is 110301112023331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133320211103011 is a prime.
It is a super-2 number, since 2×1333202111030112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (133320211103071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66660105551505 + 66660105551506.
It is an arithmetic number, because the mean of its divisors is an integer number (66660105551506).
Almost surely, 2133320211103011 is an apocalyptic number.
133320211103011 is a deficient number, since it is larger than the sum of its proper divisors (1).
133320211103011 is an equidigital number, since it uses as much as digits as its factorization.
133320211103011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 133320211103011 its reverse (110301112023331), we get a palindrome (243621323126342).
The spelling of 133320211103011 in words is "one hundred thirty-three trillion, three hundred twenty billion, two hundred eleven million, one hundred three thousand, eleven".
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