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133322203113000 = 2335311101122332707
BaseRepresentation
bin11110010100000101111110…
…100011101010011000101000
3122111001110220120021121002120
4132110011332203222120220
5114433322332444104000
61151315212524231240
740040132323221126
oct3624057643523050
9574043816247076
10133322203113000
11395316a0a55670
1212b528a009b520
1359512cab6cb75
1424ccb86d2a916
15106303a84b6a0
hex79417e8ea628

133322203113000 has 512 divisors, whose sum is σ = 458661908090880. Its totient is φ = 31973385600000.

The previous prime is 133322203112971. The next prime is 133322203113023. The reversal of 133322203113000 is 311302223331.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 4076242647 + ... + 4076275353.

It is an arithmetic number, because the mean of its divisors is an integer number (895824039240).

Almost surely, 2133322203113000 is an apocalyptic number.

133322203113000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133322203113000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (229330954045440).

133322203113000 is an abundant number, since it is smaller than the sum of its proper divisors (325339704977880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133322203113000 is a wasteful number, since it uses less digits than its factorization.

133322203113000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34066 (or 34052 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 24.

Adding to 133322203113000 its reverse (311302223331), we get a palindrome (133633505336331).

The spelling of 133322203113000 in words is "one hundred thirty-three trillion, three hundred twenty-two billion, two hundred three million, one hundred thirteen thousand".