Base | Representation |
---|---|
bin | 11000110101010101… |
… | …01100010101010110 |
3 | 1021102011002001221012 |
4 | 30122222230111112 |
5 | 204301032114032 |
6 | 10042541252222 |
7 | 651246455426 |
oct | 143252542526 |
9 | 37364061835 |
10 | 13332301142 |
11 | 57218111a6 |
12 | 2700b64072 |
13 | 134619bcb4 |
14 | 90694a486 |
15 | 5306e16b2 |
hex | 31aaac556 |
13332301142 has 4 divisors (see below), whose sum is σ = 19998451716. Its totient is φ = 6666150570.
The previous prime is 13332301133. The next prime is 13332301189. The reversal of 13332301142 is 24110323331.
13332301142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24110323331 = 313 ⋅77029787.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3333075284 + ... + 3333075287.
It is an arithmetic number, because the mean of its divisors is an integer number (4999612929).
Almost surely, 213332301142 is an apocalyptic number.
13332301142 is a deficient number, since it is larger than the sum of its proper divisors (6666150574).
13332301142 is an equidigital number, since it uses as much as digits as its factorization.
13332301142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6666150573.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13332301142 its reverse (24110323331), we get a palindrome (37442624473).
The spelling of 13332301142 in words is "thirteen billion, three hundred thirty-two million, three hundred one thousand, one hundred forty-two".
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