Base | Representation |
---|---|
bin | 11000110101010110… |
… | …00100111101110001 |
3 | 1021102011021012022220 |
4 | 30122223010331301 |
5 | 204301043331113 |
6 | 10042543351253 |
7 | 651250355526 |
oct | 143253047561 |
9 | 37364235286 |
10 | 13332402033 |
11 | 572187aa85 |
12 | 2700bb2529 |
13 | 1346205bb2 |
14 | 90697514d |
15 | 530711523 |
hex | 31aac4f71 |
13332402033 has 4 divisors (see below), whose sum is σ = 17776536048. Its totient is φ = 8888268020.
The previous prime is 13332402007. The next prime is 13332402037. The reversal of 13332402033 is 33020423331.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13332402033 - 210 = 13332401009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13332401994 and 13332402012.
It is not an unprimeable number, because it can be changed into a prime (13332402037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2222067003 + ... + 2222067008.
It is an arithmetic number, because the mean of its divisors is an integer number (4444134012).
Almost surely, 213332402033 is an apocalyptic number.
It is an amenable number.
13332402033 is a deficient number, since it is larger than the sum of its proper divisors (4444134015).
13332402033 is an equidigital number, since it uses as much as digits as its factorization.
13332402033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4444134014.
The product of its (nonzero) digits is 3888, while the sum is 24.
Adding to 13332402033 its reverse (33020423331), we get a palindrome (46352825364).
The spelling of 13332402033 in words is "thirteen billion, three hundred thirty-two million, four hundred two thousand, thirty-three".
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