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133324040031 = 3713488366447
BaseRepresentation
bin111110000101010111…
…0110110011101011111
3110202010120200222022120
41330022232312131133
54141021423240111
6141125340514023
712426615433110
oct1741256663537
9422116628276
10133324040031
11515a6a43656
1221a09b4b913
13c759753120
14664ab42207
153704ab4406
hex1f0abb675f

133324040031 has 16 divisors (see below), whose sum is σ = 218788168704. Its totient is φ = 70324768224.

The previous prime is 133324040027. The next prime is 133324040033. The reversal of 133324040031 is 130040423331.

It is not a de Polignac number, because 133324040031 - 22 = 133324040027 is a prime.

It is a super-2 number, since 2×1333240400312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133324039983 and 133324040010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133324040033) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 244182951 + ... + 244183496.

It is an arithmetic number, because the mean of its divisors is an integer number (13674260544).

Almost surely, 2133324040031 is an apocalyptic number.

133324040031 is a deficient number, since it is larger than the sum of its proper divisors (85464128673).

133324040031 is a wasteful number, since it uses less digits than its factorization.

133324040031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 488366470.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 133324040031 its reverse (130040423331), we get a palindrome (263364463362).

The spelling of 133324040031 in words is "one hundred thirty-three billion, three hundred twenty-four million, forty thousand, thirty-one".

Divisors: 1 3 7 13 21 39 91 273 488366447 1465099341 3418565129 6348763811 10255695387 19046291433 44441346677 133324040031