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13332550643 is a prime number
BaseRepresentation
bin11000110101010111…
…01001001111110011
31021102011112202011222
430122223221033303
5204301113110033
610042550455255
7651251545016
oct143253511763
937364482158
1013332550643
1157219716a5
12270106452b
131346258729
149069b337d
15530740598
hex31aae93f3

13332550643 has 2 divisors, whose sum is σ = 13332550644. Its totient is φ = 13332550642.

The previous prime is 13332550633. The next prime is 13332550669. The reversal of 13332550643 is 34605523331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13332550643 - 226 = 13265441779 is a prime.

It is a super-4 number, since 4×133325506434 (a number of 42 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (13332550603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666275321 + 6666275322.

It is an arithmetic number, because the mean of its divisors is an integer number (6666275322).

Almost surely, 213332550643 is an apocalyptic number.

13332550643 is a deficient number, since it is larger than the sum of its proper divisors (1).

13332550643 is an equidigital number, since it uses as much as digits as its factorization.

13332550643 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 35.

The spelling of 13332550643 in words is "thirteen billion, three hundred thirty-two million, five hundred fifty thousand, six hundred forty-three".