Base | Representation |
---|---|
bin | 1100001000000101101010… |
… | …1100101011010110000111 |
3 | 1202012122001200012022002211 |
4 | 3002001122230223112013 |
5 | 3221422142114214403 |
6 | 44205050332444251 |
7 | 2544166436215411 |
oct | 302013254532607 |
9 | 52178050168084 |
10 | 13333100148103 |
11 | 428059949319a |
12 | 15b4064319687 |
13 | 7593c9229678 |
14 | 34147b2079b1 |
15 | 181c57be706d |
hex | c205ab2b587 |
13333100148103 has 4 divisors (see below), whose sum is σ = 13333109845968. Its totient is φ = 13333090450240.
The previous prime is 13333100148077. The next prime is 13333100148127. The reversal of 13333100148103 is 30184100133331.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13333100148103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13333100148803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2361226 + ... + 5678167.
It is an arithmetic number, because the mean of its divisors is an integer number (3333277461492).
Almost surely, 213333100148103 is an apocalyptic number.
13333100148103 is a deficient number, since it is larger than the sum of its proper divisors (9697865).
13333100148103 is an equidigital number, since it uses as much as digits as its factorization.
13333100148103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9697864.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 13333100148103 in words is "thirteen trillion, three hundred thirty-three billion, one hundred million, one hundred forty-eight thousand, one hundred three".
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