Base | Representation |
---|---|
bin | 111110000101100110… |
… | …1011010110010011111 |
3 | 110202011010210002020210 |
4 | 1330023031122302133 |
5 | 4141031001200101 |
6 | 141130224343503 |
7 | 12430043516013 |
oct | 1741315326237 |
9 | 422133702223 |
10 | 133332053151 |
11 | 51600516a70 |
12 | 21a10774b93 |
13 | c75b2ca50b |
14 | 664bc2a543 |
15 | 37056487d6 |
hex | 1f0b35ac9f |
133332053151 has 16 divisors (see below), whose sum is σ = 194622837120. Its totient is φ = 80521761120.
The previous prime is 133332053137. The next prime is 133332053213. The reversal of 133332053151 is 151350233331.
It is not a de Polignac number, because 133332053151 - 218 = 133331791007 is a prime.
It is a super-2 number, since 2×1333320531512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133332053951) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7129116 + ... + 7147793.
It is an arithmetic number, because the mean of its divisors is an integer number (12163927320).
Almost surely, 2133332053151 is an apocalyptic number.
133332053151 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
133332053151 is a deficient number, since it is larger than the sum of its proper divisors (61290783969).
133332053151 is a wasteful number, since it uses less digits than its factorization.
133332053151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14277206.
The product of its (nonzero) digits is 12150, while the sum is 30.
Adding to 133332053151 its reverse (151350233331), we get a palindrome (284682286482).
The spelling of 133332053151 in words is "one hundred thirty-three billion, three hundred thirty-two million, fifty-three thousand, one hundred fifty-one".
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