Base | Representation |
---|---|
bin | 11110010100010000010100… |
… | …101101001000100101111001 |
3 | 122111002112120202211021020122 |
4 | 132110100110231020211321 |
5 | 114434013110400104032 |
6 | 1151324251124503025 |
7 | 40041004525162232 |
oct | 3624202455104571 |
9 | 574075522737218 |
10 | 133333312113017 |
11 | 39536381771815 |
12 | 12b54a8054aa75 |
13 | 595237b53c663 |
14 | 24cd51c492089 |
15 | 106348ac6c012 |
hex | 794414b48979 |
133333312113017 has 2 divisors, whose sum is σ = 133333312113018. Its totient is φ = 133333312113016.
The previous prime is 133333312113011. The next prime is 133333312113047. The reversal of 133333312113017 is 710311213333331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 88308420329536 + 45024891783481 = 9397256^2 + 6710059^2 .
It is a cyclic number.
It is not a de Polignac number, because 133333312113017 - 220 = 133333311064441 is a prime.
It is not a weakly prime, because it can be changed into another prime (133333312113011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666656056508 + 66666656056509.
It is an arithmetic number, because the mean of its divisors is an integer number (66666656056509).
Almost surely, 2133333312113017 is an apocalyptic number.
It is an amenable number.
133333312113017 is a deficient number, since it is larger than the sum of its proper divisors (1).
133333312113017 is an equidigital number, since it uses as much as digits as its factorization.
133333312113017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30618, while the sum is 35.
Adding to 133333312113017 its reverse (710311213333331), we get a palindrome (843644525446348).
The spelling of 133333312113017 in words is "one hundred thirty-three trillion, three hundred thirty-three billion, three hundred twelve million, one hundred thirteen thousand, seventeen".
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