Base | Representation |
---|---|
bin | 11110010100010000010101… |
… | …111101000101010000001001 |
3 | 122111002112122020021000222221 |
4 | 132110100111331011100021 |
5 | 114434013131231231412 |
6 | 1151324253154014041 |
7 | 40041005201260633 |
oct | 3624202575052011 |
9 | 574075566230887 |
10 | 133333333070857 |
11 | 39536392586747 |
12 | 12b54a87577321 |
13 | 5952382999a4a |
14 | 24cd521189a53 |
15 | 106348ca0bb07 |
hex | 794415f45409 |
133333333070857 has 2 divisors, whose sum is σ = 133333333070858. Its totient is φ = 133333333070856.
The previous prime is 133333333070719. The next prime is 133333333070869. The reversal of 133333333070857 is 758070333333331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 133277304287241 + 56028783616 = 11544579^2 + 236704^2 .
It is a cyclic number.
It is not a de Polignac number, because 133333333070857 - 215 = 133333333038089 is a prime.
It is not a weakly prime, because it can be changed into another prime (133333333070897) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666666535428 + 66666666535429.
It is an arithmetic number, because the mean of its divisors is an integer number (66666666535429).
Almost surely, 2133333333070857 is an apocalyptic number.
It is an amenable number.
133333333070857 is a deficient number, since it is larger than the sum of its proper divisors (1).
133333333070857 is an equidigital number, since it uses as much as digits as its factorization.
133333333070857 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12859560, while the sum is 52.
The spelling of 133333333070857 in words is "one hundred thirty-three trillion, three hundred thirty-three billion, three hundred thirty-three million, seventy thousand, eight hundred fifty-seven".
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