Base | Representation |
---|---|
bin | 10011011001110110000… |
… | …101111110100001000010 |
3 | 11201110210102010021110102 |
4 | 103121312011332201002 |
5 | 133321321302440114 |
6 | 2500322030402402 |
7 | 165223263452414 |
oct | 23316605764102 |
9 | 4643712107412 |
10 | 1333421140034 |
11 | 474556520385 |
12 | 196514060402 |
13 | 989831a7649 |
14 | 487761049b4 |
15 | 24a430802de |
hex | 1367617e842 |
1333421140034 has 4 divisors (see below), whose sum is σ = 2000131710054. Its totient is φ = 666710570016.
The previous prime is 1333421140031. The next prime is 1333421140039. The reversal of 1333421140034 is 4300411243331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 899752793809 + 433668346225 = 948553^2 + 658535^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1333421139979 and 1333421140006.
It is not an unprimeable number, because it can be changed into a prime (1333421140031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333355285007 + ... + 333355285010.
Almost surely, 21333421140034 is an apocalyptic number.
1333421140034 is a deficient number, since it is larger than the sum of its proper divisors (666710570020).
1333421140034 is an equidigital number, since it uses as much as digits as its factorization.
1333421140034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 666710570019.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 1333421140034 its reverse (4300411243331), we get a palindrome (5633832383365).
The spelling of 1333421140034 in words is "one trillion, three hundred thirty-three billion, four hundred twenty-one million, one hundred forty thousand, thirty-four".
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