Base | Representation |
---|---|
bin | 11110010100011001101110… |
… | …101010101001001010101011 |
3 | 122111010111122121022100202012 |
4 | 132110121232222221022223 |
5 | 114434144301301002133 |
6 | 1151333041214230135 |
7 | 40041513016214405 |
oct | 3624315652511253 |
9 | 574114577270665 |
10 | 133343411344043 |
11 | 3953a6944a253a |
12 | 12b56a1a7b534b |
13 | 59532ca9615c4 |
14 | 24cdbd9885b75 |
15 | 106387c6cbb48 |
hex | 79466eaa92ab |
133343411344043 has 2 divisors, whose sum is σ = 133343411344044. Its totient is φ = 133343411344042.
The previous prime is 133343411343941. The next prime is 133343411344067. The reversal of 133343411344043 is 340443114343331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133343411344043 - 212 = 133343411339947 is a prime.
It is not a weakly prime, because it can be changed into another prime (133343411344093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66671705672021 + 66671705672022.
It is an arithmetic number, because the mean of its divisors is an integer number (66671705672022).
Almost surely, 2133343411344043 is an apocalyptic number.
133343411344043 is a deficient number, since it is larger than the sum of its proper divisors (1).
133343411344043 is an equidigital number, since it uses as much as digits as its factorization.
133343411344043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 746496, while the sum is 41.
Adding to 133343411344043 its reverse (340443114343331), we get a palindrome (473786525687374).
The spelling of 133343411344043 in words is "one hundred thirty-three trillion, three hundred forty-three billion, four hundred eleven million, three hundred forty-four thousand, forty-three".
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