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133354970081 is a prime number
BaseRepresentation
bin111110000110010010…
…0110101101111100001
3110202012201220101100222
41330030210311233201
54141102333020311
6141132403452425
712430442354144
oct1741444655741
9422181811328
10133354970081
1151612449883
1221a18387115
13c762c92528
146650cb405b
153707673adb
hex1f0c935be1

133354970081 has 2 divisors, whose sum is σ = 133354970082. Its totient is φ = 133354970080.

The previous prime is 133354970057. The next prime is 133354970087. The reversal of 133354970081 is 180079453331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83010829456 + 50344140625 = 288116^2 + 224375^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133354970081 is a prime.

It is a super-2 number, since 2×1333549700812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133354970087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66677485040 + 66677485041.

It is an arithmetic number, because the mean of its divisors is an integer number (66677485041).

Almost surely, 2133354970081 is an apocalyptic number.

It is an amenable number.

133354970081 is a deficient number, since it is larger than the sum of its proper divisors (1).

133354970081 is an equidigital number, since it uses as much as digits as its factorization.

133354970081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 272160, while the sum is 44.

The spelling of 133354970081 in words is "one hundred thirty-three billion, three hundred fifty-four million, nine hundred seventy thousand, eighty-one".