Base | Representation |
---|---|
bin | 111110000110010010… |
… | …0111010101001000011 |
3 | 110202012201221101220011 |
4 | 1330030210322221003 |
5 | 4141102334141042 |
6 | 141132404125351 |
7 | 12430442466511 |
oct | 1741444725103 |
9 | 422181841804 |
10 | 133354990147 |
11 | 51612462965 |
12 | 21a18396857 |
13 | c762c9b6c2 |
14 | 6650cbb4b1 |
15 | 3707679a17 |
hex | 1f0c93aa43 |
133354990147 has 2 divisors, whose sum is σ = 133354990148. Its totient is φ = 133354990146.
The previous prime is 133354990123. The next prime is 133354990157. The reversal of 133354990147 is 741099453331.
It is a strong prime.
It is an emirp because it is prime and its reverse (741099453331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133354990147 - 27 = 133354990019 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133354990147.
It is not a weakly prime, because it can be changed into another prime (133354990157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66677495073 + 66677495074.
It is an arithmetic number, because the mean of its divisors is an integer number (66677495074).
Almost surely, 2133354990147 is an apocalyptic number.
133354990147 is a deficient number, since it is larger than the sum of its proper divisors (1).
133354990147 is an equidigital number, since it uses as much as digits as its factorization.
133354990147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1224720, while the sum is 49.
The spelling of 133354990147 in words is "one hundred thirty-three billion, three hundred fifty-four million, nine hundred ninety thousand, one hundred forty-seven".
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