Base | Representation |
---|---|
bin | 11110010100101011010000… |
… | …111101110010111010111011 |
3 | 122111012022020211111120020011 |
4 | 132110223100331302322323 |
5 | 114440001332020313313 |
6 | 1151345433434242351 |
7 | 40043050432443421 |
oct | 3624532075627273 |
9 | 574168224446204 |
10 | 133362240401083 |
11 | 39547676a61801 |
12 | 12b5a5b45863b7 |
13 | 595500b879785 |
14 | 24d0aa4443111 |
15 | 10640d074b93d |
hex | 794ad0f72ebb |
133362240401083 has 2 divisors, whose sum is σ = 133362240401084. Its totient is φ = 133362240401082.
The previous prime is 133362240401069. The next prime is 133362240401087. The reversal of 133362240401083 is 380104042263331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133362240401083 - 25 = 133362240401051 is a prime.
It is not a weakly prime, because it can be changed into another prime (133362240401087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66681120200541 + 66681120200542.
It is an arithmetic number, because the mean of its divisors is an integer number (66681120200542).
Almost surely, 2133362240401083 is an apocalyptic number.
133362240401083 is a deficient number, since it is larger than the sum of its proper divisors (1).
133362240401083 is an equidigital number, since it uses as much as digits as its factorization.
133362240401083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 40.
The spelling of 133362240401083 in words is "one hundred thirty-three trillion, three hundred sixty-two billion, two hundred forty million, four hundred one thousand, eighty-three".
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