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13340025113 is a prime number
BaseRepresentation
bin11000110110010000…
…01010000100011001
31021102200121111020012
430123020022010121
5204310021300423
610043415011305
7651402225332
oct143310120431
937380544205
1013340025113
115726107348
122703669b35
1313479748ac
1490799b289
1553121a078
hex31b20a119

13340025113 has 2 divisors, whose sum is σ = 13340025114. Its totient is φ = 13340025112.

The previous prime is 13340025109. The next prime is 13340025161. The reversal of 13340025113 is 31152004331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12111662809 + 1228362304 = 110053^2 + 35048^2 .

It is a cyclic number.

It is not a de Polignac number, because 13340025113 - 22 = 13340025109 is a prime.

It is a super-3 number, since 3×133400251133 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13340025163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670012556 + 6670012557.

It is an arithmetic number, because the mean of its divisors is an integer number (6670012557).

Almost surely, 213340025113 is an apocalyptic number.

It is an amenable number.

13340025113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13340025113 is an equidigital number, since it uses as much as digits as its factorization.

13340025113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 13340025113 its reverse (31152004331), we get a palindrome (44492029444).

The spelling of 13340025113 in words is "thirteen billion, three hundred forty million, twenty-five thousand, one hundred thirteen".