Base | Representation |
---|---|
bin | 10011011010011000110… |
… | …111011010100100010111 |
3 | 11201112022001212022122102 |
4 | 103122120313122210113 |
5 | 133324020124302320 |
6 | 2500455550352315 |
7 | 165243606242246 |
oct | 23323067324427 |
9 | 4645261768572 |
10 | 1334004525335 |
11 | 474825860399 |
12 | 1966574bb69b |
13 | 98a47006951 |
14 | 487cd7a495d |
15 | 24a793ba175 |
hex | 13698dda917 |
1334004525335 has 4 divisors (see below), whose sum is σ = 1600805430408. Its totient is φ = 1067203620264.
The previous prime is 1334004525317. The next prime is 1334004525379. The reversal of 1334004525335 is 5335254004331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1334004525335 - 240 = 234492897559 is a prime.
It is a super-2 number, since 2×13340045253352 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133400452529 + ... + 133400452538.
It is an arithmetic number, because the mean of its divisors is an integer number (400201357602).
Almost surely, 21334004525335 is an apocalyptic number.
1334004525335 is a deficient number, since it is larger than the sum of its proper divisors (266800905073).
1334004525335 is an equidigital number, since it uses as much as digits as its factorization.
1334004525335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 266800905072.
The product of its (nonzero) digits is 324000, while the sum is 38.
Adding to 1334004525335 its reverse (5335254004331), we get a palindrome (6669258529666).
The spelling of 1334004525335 in words is "one trillion, three hundred thirty-four billion, four million, five hundred twenty-five thousand, three hundred thirty-five".
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